Menu in a table - Placement

[baetmaen]

Hi,

I'm trying to place a horizontal menu "in a table" like shown in the example.

I have problems finding the right values for these variables:
[code:m4m1gjmlda]
//Menu properties
oCMenu.pxBetween=1
//Using the cm_page object to place the menu ----
//There are some differences between the browsers that I try to fix here.
oCMenu.fromLeft=!bw.ns4?cmpage.x2 - 586:cmpage.x2 - 586
//We also need to "replace" the menu on resize. So:
oCMenu.onresize="oCMenu.fromLeft=cmpage.x2 - 586"


oCMenu.fromTop=100
oCMenu.rows=1
oCMenu.menuPlacement=0
[/code:m4m1gjmlda]
The page where I'm trying to do this can be found on this temporary storage: [url:m4m1gjmlda]http://vps.ath.cx/oil[/url:m4m1gjmlda].

The Page itself is 757 pixxels width, and centered. I have to add the menu below the top grafic before the main area starts.

Thanks in advance
Joerg

[baetmaen]

Sorry, wrng Forum, I use Version 4 [:0]

[dp009]

I have same kind of problem!!
I am trying to make diffrent item of menu with diffrent width.
in config.js it says : "oCMenu.level[0].width=100 //The default width for each level[0] (top) items. You can override this on each item by spesifying the width when making the item. - Value: px || "%""

Here, What I do in menu-config.xml to create menu...
<Menu name="ToDoListMenuFile" title="FILE" description="test" width="50">
<Item name="TDLnewcase" title="CASE" width="80 px" location="NewCase.jsp"/>
<Item name="TDLnewitem" title="ITEM" width="110px" location="index.jsp"/>
<Item name="TDLnewparty" title="PARTY" location="index.jsp"/>
</Menu>

If someone know how to deal with this pl let me know!!

Thanks
DP